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I have a Kitchenaid cooktop model KECC567 (5 burner model) with a 2 element burner that will not cycle on or off no matter what control switch setting is used. The 2 elements of the burner stay on continuously when the dual side is selected as does the single element when it is selected on the switch. I have replaced the infinite switch but the problem still exists. Appreciate some suggestions on resolution of this problem. Has to be a temperature sensor but don't know where to look for it. Thanks

  • Can you post the wiring diagram for your stove? (It should be on one of the inside panels somewhere) – ThreePhaseEel Jul 18 '16 at 0:29
  • How do you know the elements are suppposed to cycle? They may very well be designed to run at continuous current, not a set temperature point. Take a look at the owner's manual for starters. – Carl Witthoft Jul 18 '16 at 14:07
  • Burners needs to cycle on and off to prevent overheating the ceran glass cover similar to what the other 4 burners on the cooktop do. Turns out the infinite switch on the 2 coil burner was faulty. Thanks for your response. – Kelly Hawk Jul 19 '16 at 2:48
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This is for future reference in case anyone is looking for similar information. The OP noted in a comment that

the infinite switch on the 2 coil burner was faulty.

So, it should indeed cycle

to prevent overheating the ceran glass cover similar to what the other 4 burners on the cooktop do.

P.S. Marking this CW since it isn't really my answer.

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Well, I looked at the manual, at this site , and I see no indication that the power should ever cycle on/off. I think you misunderstand what the various settings levels do -- they just control the power level fed to the burners.

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    That's correct but the burner needs to cycle on and off to prevent overheating the ceran glass cover similar to what the other 4 burners on the cooktop do. Turns out the infinite switch on the 2 coil burner was faulty. Thanks for your response. – Kelly Hawk Jul 19 '16 at 2:47
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    @KellyHawk good to know. You should post that as an answer for future readers. I'll delete my answer after that. – Carl Witthoft Jul 19 '16 at 16:44

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