i'm a noob/have rudimentary knowledge about batteries in series and parallel. i'll explain what i'm doing and would like your input as how to solve my problem.
i have 2 doorbells, one at the front of the house and one at the back.
please see attached photo of one doorbell to see how i've connected things up.
a 9v battery is attached to the black & red wires at the bottom. this doorbell uses the lower left & right terminals (at the top, where the white wires are) to connect to the push button. this forms one circuit.
then, the upper left & right terminals are connected to the other doorbell. that forms another circuit. that doorbell uses 4xAA batteries. so 6v.
as far as i can tell, both doorbells (batteries) are +ve to +ve.
so, first question: is this a series or parallel circuit?
what seems to be happening is that the 9v battery is draining/leaking because it becomes dead within a few weeks/months even if not used - ie not many people ringing the doorbell.
next question: how do i solve this 9v & 6v problem?
can i use a diode to stop the 9v battery leaking to the 6v one? how do i work out which diode i need to use?
or can it not be done? ie cannot make a 9v and a 6v parallel circuit work? (i'm assuming it is parallel).
or is there another way of configuring the wires so the 2 doorbells are separate? eg rather than using the upper terminals for the 2nd doorbell, i connect it directly to the push button? but then, the wires for both doorbells will be touching each other at the push button, and won't that also make a circuit and cause problems?
ok, over to you good people to give me the correct solution. thanks in advance.
the top circuit diagram shows the current and voltage if the first doorbell was by itself. the next circuit diagram shows the current and voltage if the second doorbell was by itself. however, I have the doorbells set up as in the last circuit diagram and there is a drain from the 9v battery into the 6v battery.