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Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Trying to wrap my head around Harper's method of finding power usage: multiply average leg current by 240V -- 240 * (L1+L2)/2. Mathematically, it's equivalent to 120V * sum of legs: 120 * (L1 + L2), so hmm.

Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Trying to wrap my head around Harper's method of finding power usage: multiply average leg current by 240V -- 240 * (L1+L2)/2. Mathematically, it's equivalent to 120V * sum of legs: 120 * L1 + L2, so hmm.

Here are some diagrams which might be helpful snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Trying to wrap my head around Harper's method of finding power usage: multiply average leg current by 240V 240 * (L1+L2)/2. Mathematically, it's equivalent to 120V * sum of legs: 120 * (L1 + L2), so hmm.

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Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Trying to wrap my head around Harper's method of finding power usage: multiply average leg current by 240V -- 240 * (L1+L2)/2. Mathematically, it's equivalent to 120V * sum of legs: 120 * L1 + L2, so hmm.

Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Trying to wrap my head around Harper's method of finding power usage: multiply average leg current by 240V -- 240 * (L1+L2)/2. Mathematically, it's equivalent to 120V * sum of legs: 120 * L1 + L2, so hmm.

deleted 95 characters in body
Source Link

Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Took me a while to figure out Harper's method of finding total usage: (L1 + L2)/2 * 240V.

Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

Took me a while to figure out Harper's method of finding total usage: (L1 + L2)/2 * 240V.

Here are some diagrams which might be helpful -- snapshots of a circuit simulation.

Both circuits have identical total power consumed, just different 120V loads.

circuit diagrams

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