Take the 2-minute tour ×
Home Improvement Stack Exchange is a question and answer site for contractors and serious DIYers. It's 100% free, no registration required.

I've got some limited field experience as an electrical helper, but no real classroom experience yet. (saving up for school)

I am of the understanding that the neutral wire carries electricity back to a breaker panel.

I generally wire switches, as instructed, as follows:

enter image description here

However, this doesn't make sense to me because if the switch is in the off position, how does the power return to the breaker panel? I assume it can't be flowing through the neutral because the path to the device is interrupted by the switch, thus the circuit is not complete.

Does it flow, instead, through the ground? I've been told that the ground should never have current unless there is a severe fault, at which point there is a problem that needs fixing.

Isn't the ground the only way the electricity would return to the breaker panel in the above wiring scheme?

share|improve this question

4 Answers 4

up vote 11 down vote accepted

The switch opens (turns off) the circuit, at which point electricity is not "flowing" through the circuit. The electricity flows to the first terminal on the switch, and then just sits there. Think of it like a closed plumbing valve. When the valve is closed, water flows to the valve, and then just sits there. Once the valve is opened, the water can then flow through the plumbing.

share|improve this answer
    
+1 If I knew as much as you, I could be faster on the keys. –  bib Jan 27 at 17:57
    
Thanks for the answer. That makes a lot of sense. I've been taught to think of electricity as water, so I should've thought of that! One more question: What stops the switch from heating up with the electricity just sitting there? For example, if you ran hot water through a copper pipe, I'd expect the pipe to get hot at every point where the water was in contact. Does this mean there is some heat resistant material where the circuit opens? –  user19512 Jan 27 at 18:05
2  
Electricity only generates heat when it is "flowing". When current meets resistance, heat is made. If there is no current, or no resistance, there is no heat. Don't forget, voltage is only the potential, current is what makes changes. –  Tester101 Jan 27 at 18:16
    
This answer has some gifs in it that might help you understand switches a bit better. You'll notice how the electricity only "flows" when the switch is closed. –  Tester101 Jan 27 at 18:30
4  
Don't take the "water analogy" too seriously -- there are some similarities between electrical flow and water flow, but the analogy only holds true at the most basic level, and you can't apply the properties of water to electricity, so there is no "hot" and "cold" electricity. –  Johnny Jan 27 at 19:22

It doesn't flow. When the switch is off (open) no current is running in that particular circuit. While there is a high potential on the black hot line at the switch, that is not part of a flowing current until the switch is closed and the current then flows through the fixture and then back to the panel through the white neutral wire attached at the fixture (and incidentally joined in the switch box).

You seem to think that current must be flowing at all times. That is not the case.

share|improve this answer

In addition to the other good answers I would add that you are making the common beginner mistake of confusing current with voltage. There is certainly voltage on one side of an open (that is, off) switch.

In your "water" analogy, voltage is the pressure in the pipe and current is the rate at which it is flowing. If you shut a valve on a pipe then the pressure stays high on one side, drops to zero on the other side, and therefore the flow out of the pipe stops.

The neutral is like the drain of a sink. There is never any pressure in a drainpipe but surely there is flow.

Some useful facts that you should assimilate deeply into your brain are:

  • The current through a circuit that does not branch is the same at every point in the circuit. Again, think of the water analogy; the amount of water flowing past a given point per second is the same everywhere, provided that the pipes do not branch.
  • This means that if the current is zero at one point in the circuit, it is zero everywhere.
  • It also means that if there are two points on a circuit with different currents, there must be a branch -- typically current leaking to ground, dangerously -- somewhere.
  • Again, do not confuse current with voltage. The voltage need not be the same everywhere, and in fact is not.

Also you should make sure that you understand the two fundamental relationships between current, voltage, resistance and power:

  • current is voltage divided by resistance. This should make sense. Moving a lot of stuff requires either a very slippery pipe, or a lot of pressure. An open switch is essentially a point of extremely high resistance. (Of course even an open switch will conduct electricity if the voltage is high enough; hit it with a bolt of lightning and see what happens.)
  • power (watts) is current (amps) times voltage (volts). Again, this should make sense. Power is the amount of energy being consumed per second. If you're moving a lot of stuff at high pressure then you are consuming a lot of energy very quickly. If you;re moving absolutely nothing (zero current) at any pressure, you're consuming zero energy.

So now, see if you can answer these questions:

  • Suppose we hook up two hot wires of the same voltage to two different light bulbs of the same wattage, and connect both light bulbs to a single neutral wire. What is the relationship between the current on the neutral and the current on the hots?
  • Is this dangerous? Explain why or why not.
share|improve this answer
    
Spoken like an engineer. I like the little puzzle you threw in there. :-) –  Jeffrey Hantin Jan 28 at 1:15
    
The answer to you question depends on the source and phase of the voltage on each hot wire. –  Tester101 Jan 28 at 1:21
    
@Tester101: You are right. Let's suppose that we're in a normal US household with 240V one phase power split in half, so half the panel appears out of phase with the other half. What are the possibilities? –  Eric Lippert Jan 28 at 3:39
    
Then you'll have double the current on the neutral, if the ungrounded (hot) conductors are on the same leg. Or 0 current on the neutral, if the ungrounded (hot) conductors are on different legs. However, if they are on the same leg, you shouldn't be sharing a neutral. –  Tester101 Jan 28 at 3:46
2  
@user19512: You did confuse voltage with current again but you are on the right track. Remember, the voltage on the neutral is zero; it's the current you have to worry about because its the current that can make the wire get warm enough to burn. An edison circuit can lead to overcurrent on the neutral because most people think that the neutral should be the same gauge as the hot; but that's only true if the current is the same. Worse: the overcurrent protection -- the breakers -- is on the hots! –  Eric Lippert Jan 28 at 14:52

The neutral is a the completion of a circuit back to the power source/transformer. It meets up with the ground at a main bond in the first electrical enclosure downstream of the meter or main disconnect. It also is performed in a separately derived system via a transformer installed to change the voltage desired for circuitry. If you have 480 volts a/c and want 120/208 you set a transformer fed with 480 and on the secondary you have 120/208 volts requiring a main bond on the secondary for fault situations to that power source. That transformer has now become a separately derived system. This bond brings the equipment grounding conductors, grounding electrode conductors, lightning protection conductors, and neutral together to form one path back to the power source to allow for any ground faults to facilitate the proper operation of tripping a breaker or blowing a fuse. This main bond only should happen one time at the service entrance of a house, building, etc. on the load side of the main service disconnect. From there on out the grounding conductor(green wire, bare wire, all metallic eqipment to be grounded) and the neutral are to be strictly separated. If another panel is installed downstream from the main panel, then in that panel the grounding (greens, and bares) are isolated from the neutral/grounded (whites and grays). Ground rods and your other supplemental grounging electrodes are in place to dissipate major overvoltages from power company line surges and lightning strikes. THEY ARE NOT INTENDED TO PROTECT PEOPLE AND EQUIPMENT FROM LINE TO GROUND FAULTS! If your system is not bonded and a fault occurs, then you have a very dangerous situation. There is no place for the fault find its way back to the power source and create fault current situation to trip the breaker and or blow the fuse. Basically this fault is like a snake waiting to bite if the condition presents itself because the breaker has not tripped or the fuse blown.

share|improve this answer
1  
Does not actually answer the question asked - talks about something else completely. –  The Evil Greebo Jun 18 at 12:45

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.